Question

answer the 23rd or question

Answer 1

We know that the diagonals of a rhombus r perpendicular to each other... so,

Let the side of a rhombus be x...

By using Pythagoras theorem...

3² + 4² = x²
or, x = 5

Also all the sides of a rhombus r equal....

Therefore perimeter of the rhombus = 4×5
= 20cm

Hope it helped....

Answer 2

hey!! your answer is --

Let ABCD is a given rhombus
Perimeter of ABCD

=AB+BC+CD+DA

=4AB [All sides are equal]

=4(AO)2+(DO)2−−−−−−−−−−−−=4√(AO)2+(DO)2 [The diagonals are perpendicular to each other, and Pythagoras Theorem]

=4(AC2)2+(BD2)2−−−−−−−−−−−−=4√(AC2)2+(BD2)2 [The diagonals bisect each other]

=4(AC)24+(BD)24−−−−−−−−−−−=4√(AC)24+(BD)24

=42(AC)2+(BD)2−−−−−−−−−−−−√=42(AC)2+(BD)2

=2(AC)2+(BD)2−−−−−−−−−−−−√

= 2 × √ 8^2 + 6^2
= 2 √ 64 + 36
= 2 × 10

= 20 cm

hence , perimeter of rhombus is 20 cm