Answer the 2nd part to get 15+ points.
Class 10th electricity
Thank you♥️
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from i
using kvl
I=1A
v=10
so Rbulb=5 ohm
now in ii
10 ohm parallel to 10 ohm so Current will half.
I.e .5 A
now potential across bulb =5*.5=2.5 ans.
by Rajat
using kvl
I=1A
v=10
so Rbulb=5 ohm
now in ii
10 ohm parallel to 10 ohm so Current will half.
I.e .5 A
now potential across bulb =5*.5=2.5 ans.
by Rajat
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