answer the 2nd question
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3
v=u+at
v=10-2×5
v=0
after 5 sec particle will stop
s=ut+1/2at^2
=10×5-1/2×2×25
=25mt
so after travelling 25mt in 5sec particle will stop so final velocity is 0
v=10-2×5
v=0
after 5 sec particle will stop
s=ut+1/2at^2
=10×5-1/2×2×25
=25mt
so after travelling 25mt in 5sec particle will stop so final velocity is 0
Answered by
0
velocity is zero and the body is at rest
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