Question

answer the 3 Question

Answer 1

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Answer 2

in quadrilateral P0RQ

Angle POR = 90° + (angleQ / 2)

Angle POR = 90° + (100/ 2)

= 90° + 50° = 140°

Angle POR = 140°

AngleOPR and angle ORP will be equal acute angles.

in triangle POR,

Angle OPR + angleORP + 140° = 180°

angleOPR + Angle ORP = 40°

since , PO = OR ( radii of circle are always equal)

so then ,

AngleOPR = angleORP = 20°

Answer:
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AngleOPR = 20° , angle ORP = 20°