Math, asked by Abhishek5501, 5 months ago

Answer the 33th question rightly and I'll mark it as brainliest.

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Answered by adityak4m6le007

Answer:

L.H.S. = cos2A + cos2B – cos2C = 2cos(A + B) cos(A – B) – (2 cos2C – 1) = -2cosCCos(A – B) – 2 cos2C + 1 [∵ cosC=-cos(A+B)] = 1 – 2cos C[cos(A – B) – cos (A + B)] = 1 – 2cos C[-2 sinA . sin(- B)] = 1 – 4 sin A sin B cos C = R.H.S.

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