Question

answer the 6th q....​

Answer 1

Answer:

(2x-y)(2x+y)(4x²+y²)

Step-by-step explanation:

16x⁴- y⁴

=(4x²)²-(y²)²

=(4x²-y²)(4x²+y²)

=[(2x)²-y²](4x²+y²)

=(2x-y)(2x+y)(4x²+y²)

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Answer 2

$\rm 16x⁴- y⁴ \\ \rm =(4x²)²-(y²)² \\ \rm =(4x²-y²)(4x²+y²) \\ \rm =[(2x)²-y²](4x²+y²)\\ \implies \rm\red {(2x-y)(2x+y)(4x²+y²)}$