Math, asked by ronin93, 11 months ago

Answer the A.P question ​

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Answered by yajmera8
3

a = 20

d = 58/3 - 20

=58-60/3

= - 2/3

300=n/2(2a+(n-1)d)

600=n(40+(n-1)(-2/3)

600=n(40-2/3n +2/3)

600=n(120-2n+2/3)

1800=n(122-2n)

Divide by 2 both sides

900=n(61-n)

n^2-61n+900=0

D=b^2-4ac

=3721-3600

=121

√D=11

n=61-11/2=50/2=25

n=61+11/2=72/2=36

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