answer the above attachment....
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13
Answer:
When a stone is dropped from a height h it hits the ground with a momentum.
P= m ✓2gh -----(1)
where
m= Mass of stone
When same stone is dropped from a height 2h (i.e 100% of initial ) then its momentum with which it hits ground becomes .
P' = m ✓2g(2h) => ✓2P -------(2)
% change in momentum = P'-P/ P× 100%
= √2P - P/P×100 %
= 41%
Hope it helps uh!!
Answered by
14
Answer:
When stone is droped from height h :-
When stone is droped from height 2h :-
@14riyaz14
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