Question

Answer the above attachment .. .......​

Answer 1

Answer:

p + q + 1 = 0

Step-by-step explanation:

Let "α" be the common root of given equations,then

α² + pα + q = 0

α² + qα + p = 0

$\frac{\alpha ^2}{p^2-q^2} =\frac{\alpha }{q-p} =\frac{1}{q-p}$ ⇒ α = $\frac{p^2-q^2}{q-p}$ and α = 1 ⇒ $\frac{p^2-q^2}{q-p}$ = 1

p² - q² = q - p

(p² - q²) + p - q = 0

(p - q)(p + q) + (p - q) = 0

(p - q)(p + q + 1) = 0 ⇒ p + q + 1 = 0 and p - q = 0

Answer 2

refer the attachment for the answer

hope it helps

Have a good day ahead ☺☺❤❤