Question

answer the above attachment​

Answer 1

${\huge{\boxed{\pink{\bf{Answer}}}}}$

First , rationalize the denominator...

$\frac{(3 + 5i)}{(3 - 6i)} \times \frac{(3 + 6i)}{(3 + 6i)}$

$\implies \: \frac{9 + 18i + 15i + 30 {i}^{2} }{9 + 6}$

$\implies \: \frac{9 + 33i - 30}{15}$

$\implies \: \frac{ - 21}{15} + \frac{33i}{15}$

Now , modulus =

$\sqrt{ {( \frac{ - 21}{15}) }^{2} + { (\frac{33}{15} }^{2} )}$

simplify

$\sqrt{( \frac{441 + 1089}{225}) }$

$= \sqrt{ \frac{1530}{225} }$

Dividing and multiplying by 15

$= \sqrt{ \frac{102}{15} }$

Dividing and multiplying by 3

$= \sqrt{ \frac{34}{5} }$

Option A...

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These are too easy Questions,

try them yourself...ಠ_ಠ

btw, which exam is this...?