Question

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Answer 1

GIVEN AB =3CM BC=3CM CA=4cm

$ab = r1 + r2 = 3cm \: \: \: equation1$

$bc = r2 + r3 = 3cm \: \: \: \: equation2$

$ca = r3 + r1 = 4cm \: \: \: \: equation 3$

THEREFORE AB+BC+CA=2(r1+r2+r3)=3+3+4=10

2(r1+r2+r3)=10

r1+r2+r3=10/2

r1+r2+r3=5

from equation 2..

r1+3=5

$r1 = 5 - 3 = 2cm$r1+r2+r3=5

from equation 3..

r2+4=5

$r2 = 5 - 4 = 1cm$

r1+r2+r3=5

from equation 1

3+r3=5

$r3 = 5 - 3 = 2cm$

therefore radii of each circle is r1=2cm r2=1cm r3=2cm

r1=2cm r2=1cm r3=2cmrespectively

Answer 2

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Answer:-

Refer to attachment-2 Sis