Question

answer the above-mentioned question​

Answer 1

Answer:

19 A

Explanation:

here is the explanation

Answer 2

Answer:-

• Charge=Q
• Current=I
• Time=t=2s

Here

• Q(t)=4t^2+3t+1

Substitute t as 2s

$\\ \sf\longmapsto 4t^2+3t+1$

$\\ \sf\longmapsto 4(2)^2+3(2)+1$

$\\ \sf\longmapsto 4(4)+6+1$

$\\ \sf\longmapsto 16+7$

$\\ \sf\longmapsto 23$

• Q=23C
• t=2s

We know that

$\boxed{\sf I=\dfrac{Q}{t}}$

$\\ \sf\longmapsto I=\dfrac{23}{2}$

$\\ \sf\longmapsto I=11.5A$

$\\ \sf\longmapsto I=11A(Approx)$