Question

Answer the above one pls. (Spam answers = report) ​

Answer 1

Answer:

$\frac{ {x}^{2} }{6} + \frac{ {y}^{2} }{25} - \frac{xy}{15}$

Answer 2

Question

$\large\bf \: \{\frac{x}{6} - \frac{y}{5} \} {}^{2}$

Expand the given equation

Answer

$\large\rm \: \{\frac{x}{6} - \frac{y}{5} \} {}^{2}$

$\rm\: Taking~a=\frac{x}{6}$

$\rm\: Taking~b=\frac{y}{5}$

$\rm\: Using~the~identity$

$\rm\: (a-b)²=a²+b²-2ab$

$\rm\: Substituting~the~value$

$\rm\: (\frac{x}{6}-\frac{y}{5})²=\frac{x}{6}²+\frac{y}{5}²-2\frac{x}{6}\frac{y}{5}$

$\rm\:( \frac{x}{6}-\frac{y}{5})²=\frac{x²}{36}+\frac{y²}{25}-2\frac{x}{6}\frac{y}{5}$

$\rm\: (\frac{x}{6}-\frac{y}{5})²=\frac{x²}{36}+\frac{y²}{25}-\cancel2\frac{x}{\cancel6}\frac{y}{5}$

${\boxed{\bf\: (\frac{x}{6}-\frac{y}{5})²=\frac{x²}{36}+\frac{y²}{25}-\frac{xy}{15}}}$

Basic formulas↓

${ \color{lightblue}{\boxed {\boxed {\begin{array}{c} \tt \: (a + b) {}^{2} = a {}^{2} + b {}^{2} + 2ab\\ \: \tt(a - b) {}^{2} = a {}^{2} + b {}^{2} - 2ab\\ \: \tt \:(a - b)(a + b) = a {}^{2} - b {}^{2} \: \end{array}}}}}$