Question

Answer the above question​

Answer 1

Step-by-step explanation:

xsin^3a + ycos^3a = sinacosa

or, xsin^3a + ycosa×cos^2a = sinacosa

or, xsin^3a + xsina×cos^2a = sinacosa

while, [xsina = ycosa]

or, xsina(sin^2a + cos^2a) = sinacosa

or, xsina = sinacosa [sin^2a+cos^2a = 1]

or, x = cosa

so that, y = sina [xsina=ycosa]

Finally, sin^2a + cos^2a = 1

or, x^2 + y^2 = 1 (proved).

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