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The height of the palm tree will be 15m.
- Firstly make two straight lines DE and AB
- DE must be the smaller one and AB must be the bigger one that is DE is the boy standing and AB is the palm tree.
- Join EB and AD.
- Make DC perpendicular to AB.
- In rectangle BEDC, DE=BC=1.8cm and DC=BE=13.2cm.
- The angle of elevation of the top off the tree from his eyes is 45 degree that is angle ADC is 45 degree.
- In triangle ADC , AC/DC= tan 45
- AC/13.2=1
- AC=13.2cm 8. So, AB= AC + BC
- AB=( 13.2 + 1.8)m
- AB=15m
I hope it helps u.........
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