Question

Answer the above question​

Answer 1

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Answer 2

Answer:

answer for the given problem is given

Step-by-step explanation:

Total number of Prizes =3

Total value of three prizes =Rs.330

Let the first prize be 'X'

then second prize would be 5/6X.

and third prize would be 4/5(5/6X). (given)

therefore third prize =4/6X

therefore, X+(5X/6)+(4X/6)=330

therefore, X+(5X/6)+(4X/6)=330=>(6X+5X+4X)/6=330

therefore, X+(5X/6)+(4X/6)=330=>(6X+5X+4X)/6=330=>15X/6=330

therefore, X+(5X/6)+(4X/6)=330=>(6X+5X+4X)/6=330=>15X/6=330=>15X=330×6

therefore, X+(5X/6)+(4X/6)=330=>(6X+5X+4X)/6=330=>15X/6=330=>15X=330×6=>15X=1980

therefore, X+(5X/6)+(4X/6)=330=>(6X+5X+4X)/6=330=>15X/6=330=>15X=330×6=>15X=1980=>X=1980/15

=>X=132

therefore, The value of first prize = Rs.132

then ,The value of second prize = 5/6X =

(5/6)132= (5×132)/6=660/6=110

The value of second prize = Rs.110

then the value of third prize

then the value of third prize =4/5of the second prize

=(4/5)×110=(4×110)/5=440/5=88

the value of third prize =Rs.88

Check:

sum of the three prizes =Rs.330

132+110+88 =Rs.330