Question

Answer the above question...​

Answer 1

Answer:

6x^2-5x+1

x^2-5x+6

x^2-(3+2)x+6

x^2-3x-2x+6

x(x-3)-2(x-3)

(x-3)(x-2)

If x-3=0 & x-2=0

x=3(alpha),x=2(beta)

reciprocal of alpha and beta

x=1/3(alpha),x=1/2(beta)

Now,use this formula,

x^2-(alpha+beta)x+(alpha*beta)

putting value of alpha and beta,

x^2-(1/3+1/2)x+1/3*1/2

6x^2-5x+1