ANSWER THE ABOVE QUESTION?
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Given
angle BCD = 96°
=> angle ABD + angle DAB = 96° [sum of two opposite interior angles = exterior angle]
=> (as angle ABD = 3 angle DAB) 4 angle DAB = 96°
=> angle DAB = 24°
therefore angle ABD = 3×24
= 72°
hope it helps you
angle BCD = 96°
=> angle ABD + angle DAB = 96° [sum of two opposite interior angles = exterior angle]
=> (as angle ABD = 3 angle DAB) 4 angle DAB = 96°
=> angle DAB = 24°
therefore angle ABD = 3×24
= 72°
hope it helps you
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