Question

answer the above question ​

Answer 1

for infinitely many solutions the comparison between the ratios should be a1/a2=b1/b2=c1/c2

here a1=2

a2=k+2

b1=3

b2=b

c1=k

c2=3k+2

=2/k+2=k/3k+2

by cross multiplication

= k( k+2)=2(3k+2)

k^2+2k=6k+4

k^2+2k-6k-4

k^2-4k-4

then k= 4+4√2/2 or 4-4√2/2