Question

Answer the above question according to chapter number system.

Answer 1

...here is your answer
hopes it will help you...
please mark me brainliest.....if the answer is corect

Answer 2

Answer:

$x^{3} - \frac{1}{x^{3} }= 6\sqrt{3}$

Step-by-step explanation:

Given : $x-\frac{1}{x} =\sqrt{3}$

To Find : $x^{3} -\frac{1}{x^{3} }$

Solution :

Consider the formula :

$(x-\frac{1}{x}) ^{3} = x^{3} - \frac{1}{x^{3} }- 3*x*\frac{1}{x} (x-\frac{1}{x} )$

$\sqrt{3} ^{3} = x^{3} - \frac{1}{x^{3} }- 3( \sqrt{3})$

$3\sqrt{3}= x^{3} - \frac{1}{x^{3} }- 3\sqrt{3}$

$3\sqrt{3}+3\sqrt{3}= x^{3} - \frac{1}{x^{3} }$

$6\sqrt{3}= x^{3} - \frac{1}{x^{3} }$

Thus $x^{3} - \frac{1}{x^{3} }= 6\sqrt{3}$