Answer the above question?
Best answer will be marked as Brainliest
Attachments:
Answers
Answered by
10
Lets take the LHS
(cosA-sinA)+1/(cosA+sinA)-1
taking conjugate
(cosA-sinA)+1/(cosA+sinA)-1 × (cosA+sinA)+1/(cosA+sinA)+1
multiplying we get
=cos2A-sin2A+2cosA+1/2sinAcosA
=cos2A-sin2A+2cosA+sin2A+cos2A/2sinAcosA
on solving we get
=2cos2A+2cosA/2sinAcosA
=cosA+cos2A/sinAcosA
we can alsom write in the form of
cosA/sinAcosA +cos2A/sinAcosA
on solving we get
CosecA+cotA =R.H.S
Answered by
2
Hope it helps u.....plz mark me as brainlist.....
Attachments:
Similar questions