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✪ Question :-
A circus artist is climbing a 20 m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Find the height of the pole, if the angle made by the rope with the ground level is
30°.
✪ Given :-
• AB = Vertical pole
• AC = 20 m
• ACB = 30°
✪ To Find :-
• The height of the vertical pole.
✪ Solution :-
It's given that AB is the vertical line and AC is 20 m long rope.
⇒Sin30° = AB/AC
Sin30° is 1/2, value of AB is not given and Value of AC is 20 m
⇒1/2 = AB/20
We AB from RHS will move to LHS and 2 from LHS will move to RHS.
⇒AB = 20/2
⇒AB = 10
Therefore, the height of the vertical pole is 10 m
Joyful learning!!! ⛅
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