Question

answer the above question please


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Answer 1

Answer:

A=28121.6

Step-by-step explanation:

.... Continued

A=25000×(1+$\frac{4}{100}$)^3

A=25000×($\frac{104}{100}$)^03

A=25000×($\frac{104}{100}$)×($\frac{104}{100}$)×($\frac{104}{100}$)

A=25×104×104×104/1000

A=28121600/1000

A=28121.6

There is no need to add Principal and interest as directly amount is found.

Answer 2

Answer:

Amount , A = Rs 28,000

Interest , I = Rs 3,000

Step-by-step explanation:

P = 25000

n = 3yrs

R = 4 %

A = P (1+ R/100)ⁿ

= 25000( 1 + 4/100)³

= 25000{ ( 100+4)/100}³

= 25000( 104/100)³

= 25000x(1.04)³

= 25000 x 1.124864

= 25000x 1.12

= 28,000

A = P + I

→ 28000 = 25000 + I

→ I = 28000-25000

→ I = 3000

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