Question

Answer the above question please

Answer 1

Answer:

since cos2theta + sin2theta = 1

then cos2theta = 1- sin2theta

taking square roots on both sides=

costheta= ✓1- sin2theta

hope this helps u

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Answer 2

Answer:-

$\sqrt{1 - { \sin }^{2}(\theta) } = \cos(\theta)$

Solution:-

We Know that

${ \sin}^{2} \theta+ { \cos }^{2}\theta = 1$

Transposing ${ \cos }^{2} \theta$ on Right side and 1 On Left side

${ \sin }^{2} \theta - 1 = { \cos}^{2} \theta$

$= > { \cos}^{2}\theta = { \sin }^{2} \theta - 1$

$= > \cos\theta = \sqrt{{ \sin }^{2} \theta - 1}$

So The Value of

$\sqrt{{ \sin }^{2} \theta - 1} = \cos\theta$