Question

Answer The Above Question .. :( .. Please
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Answer 1

Step-by-step explanation:

if $b$ is base and $h$ is height and $h$ is hypotenuse and $\theta$ is angle between hypotenuse and base.

then,

$\frac{ {( \frac{p}{h} )}^{2} }{ \frac{b}{h} } + \frac{b}{h}$

= $(\frac{ {p}^{2} }{ {h}^{2} } + \frac{ {b}^{2} }{ {h}^{2}} ) \frac{h}{b}$

= $\frac{ {p}^{2} + {h}^{2} }{ {h}^{2} } \times \frac{h}{b}$

= $\frac{ {h}^{2} }{ {h}^{2} } \times \frac{h}{b}$

= $\frac{h}{b} = \sec(\theta)$

hence, proved!