Question

answer the above question pls

Answer 1

let four consecutive numbers a,b,c,d

given a+b+c+d=32 ..........(1)

again given a×d:b×c=7:15 ......(2)

a,b,c,d are in A.P

let first term is A and common difference is D then

a=A-3D, b=A-D ,c=A+D, d=A+3D

from equation (1)

4A=32

A=8

from equation (2)

(A-3D)×(A+3D)/(A-D)×(A+D)=7/15

A^2-9D^2/A^2-D^2=7/15

D=2

hence a=2, b=6 ,c=10 ,d=14 Answer