Physics, asked by mail2drsarita, 8 months ago

answer the above question step by step​

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Answered by gunduravimudhiraj76
0

Answer:

Given:u=−10cm f=20cm (convex lens)

To find: v and image's nature.

Solution: From lens formula

v

1

u

1

=

f

1

v

1

+

10

1

=

20

1

v

1

=

20

−1

v=−20cm

And magnification =

u

v

=2

Hence image formed is virtual, erect and magnified two times.

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,

Explanation:

Focal length f=−20 cm

Object distance u=−50 cm

Using

v

1

u

1

=

f

1

Or

v

1

(−50)

1

=

−20

1

We get v=−14.3 cm

Since, v is negative. So image formed is virtual.

Hence, virtual image is formed at a distance of 14.3 cm in front of the lens.

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Answered by palaksingharmy
2

Explanation:

hey Army

Given

F=20cm

v=60cm

A/Q

1/v-1/u=1/f

so, 1/60 - 1/u = 1/20

1/u= 1/20 -1/60

now solving the equation

1/v = 1/30

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