Math, asked by meghanadh58, 8 months ago

answer the above question with steps​

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Answers

Answered by AvinashNanganure
1

Answer:

option2

Step-by-step explanation:

plz check the attachment for answer

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Answered by rishabh1894041
0

Answer:

 =  \sqrt{25 -  9{x}^{2} }  +  \sqrt{ {x}^{2} + x + 1 }  \\   \\ 25 -  9{x}^{2}  \geqslant 0 \\  9 {x}^{2}  - 25 \leqslant 0 \\  \frac{ - 5}{3}  \leqslant x \leqslant  \frac{5}{3} .......(1) \\  \\  {x}^{2}  + x + 1 \geqslant 0 \\ Its \: discriminant \: is \: always \: less \: than \:  \\ zero \: hence \:  {x}^{2}  + x + 1 > 0 \: for \: all \: of \: x \:  \\  \\ hence \: domain \: is \:  \frac{ -5}{3}  \leqslant x \leqslant  \frac{5}{3}  \\  \\ hope \: it \: will \: help \: you....

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