answer the above quetion.......
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arc sin x = arc tan y
arc sin x = arc tan (x/ √(1-x²) )
y √ (1-x²) = x
y²(1-x²) = x²
1/y² = 1/x² -1
So, 1/x² - 1/y² = 1
arc sin x = arc tan (x/ √(1-x²) )
y √ (1-x²) = x
y²(1-x²) = x²
1/y² = 1/x² -1
So, 1/x² - 1/y² = 1
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