Question

answer the attached file plase

Answer 1

Answer:

x=1,6

Step-by-step explanation:

${x}^{3} - 7 {x}^{2} + 6x = 0$

${x}^{2} - 7x + 6 = 0$

${x}^{2} - x - 6x + 6 = 0$

$x(x - 1) - 6(x - 1) = 0$

$(x - 1)(x - 6) = 0$

$x - 1 = 0 = > x = 1$

$x - 6 = 0 = > x = 6$