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hola mate here is your answer.....
as u can see the distance covered by the body with both velocities is equal i.e. X
so avg. velocity =. total distance ÷ total time
time in which velocity = V1 = X/ V1
time with velocity V2 =. X/ V2
so avg velocity =. X+X / ( X/V1 + X/V2 )
so avg velocity =. 2X / [ (XV2 + XV1 ) / V1V2 ]
so avg velocity =. 2 X / { x ( V2 + V1 ) / V1V2 }
=. 2/ { ( V2+V1 ) / V1V2}
hence avg velocity =.2 V1 V2 / V1 + v2
as u can see the distance covered by the body with both velocities is equal i.e. X
so avg. velocity =. total distance ÷ total time
time in which velocity = V1 = X/ V1
time with velocity V2 =. X/ V2
so avg velocity =. X+X / ( X/V1 + X/V2 )
so avg velocity =. 2X / [ (XV2 + XV1 ) / V1V2 ]
so avg velocity =. 2 X / { x ( V2 + V1 ) / V1V2 }
=. 2/ { ( V2+V1 ) / V1V2}
hence avg velocity =.2 V1 V2 / V1 + v2
Answered by
1
hope this will help you.
thank you for asking a good question.
thank you for asking a good question.
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