Question

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Answer 1

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Answer 2

★Question :

ABC is a right triangle , right angled at C .

l et BC = a, CA = b , AB = c and p be the length of perpendicular from C to AB .

Prove cp= ab .

★ Solution :

Given ; BC = a, CA = b , AB = c

and CD = p

Area ΔABC

$= \frac{1}{2} \times AD\times CD$

$= \frac{1}{2 } \times c \times p$

Also Area of ΔABC

$= \frac{1}{2} \times BC \times AC$

$= \frac{1}{2} \times a \times b$

Therefore ;

$\frac{1}{2} \times ab = \frac{1}{2} \times cp$

↪ ab = cp

Hence proved.