Question

Answer the attachment..​

Answer 1

$<marquee>❤REFER TO THE ATTACHMENT❤<marquee>$

Answer 2

Answer:

r = 2.5 cm

h = 1.75 m = 175 cm

Curved Surface Area of one iron rod:

$\tt{2 \pi r h}$

=> 2 × 22/7 × 25/10 × 175

=> 2750 sq cm

=> 0.275 sq m

For 12 iron rods = 0.275 × 12

= 3.3 sq m

Cost = Rs. 200 /-

=> 3.3 × 200

=> Rs. 660

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