Question

answer the attachment​

Answer 1

Answer:

As we know that

(a+b+c)^2= a^2+b^2+c^2+2ab+2bc+2ca

on putting the value of a^2+b^2+c^2=35

(a+b+c)^2= 35+2(ab+bc+ca)

again, on putting the value of ab+bc+ca=23

(a+b+c)^2= 35+2×23

(a+b+c)^2= 35+46

a+b+c= √81

therefore, a+b+c= 9