Question

Answer the attachment.......


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Answer 1

$\large\rm { X_{c} = X}$

When both capacitance frequency are doubled the reactance will become

$\large\rm { X'_{c} = \frac {1}{2π×(2f)×2(c)}}$

$\large\rm { = \frac {1}{4} × \frac {1}{2 \pi fc}}$

$\large\boxed{\rm { \frac {x}{4}}}$

is the required answer.

Answer 2

hope this helps you

hey Vishal