Question

Answer the attachment.......


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Answer 1

Induced emf is given by:

$\large\rm { ε= Bvl}$

On putting the values we get:

$\large\rm { = 5 × 10^{-5} × 1.50×2}$

$\large\boxed{\rm { 0.15 \ mV}}$

is the required answer.

Answer 2

Answer:

Induced emf is given by:

Induced emf is given by: { ε= Bvl}ε=Bvl

Induced emf is given by: { ε= Bvl}ε=BvlOn putting the values we get:

Induced emf is given by: { ε= Bvl}ε=BvlOn putting the values we get:{ = 5 × 10^{-5} × 1.50×2}=5×10

Induced emf is given by: { ε= Bvl}ε=BvlOn putting the values we get:{ = 5 × 10^{-5} × 1.50×2}=5×10 −5

Induced emf is given by: { ε= Bvl}ε=BvlOn putting the values we get:{ = 5 × 10^{-5} × 1.50×2}=5×10 −5 ×1.50×2

Induced emf is given by: { ε= Bvl}ε=BvlOn putting the values we get:{ = 5 × 10^{-5} × 1.50×2}=5×10 −5 ×1.50×2{\rm { 0.15 \ mV}}

Induced emf is given by: { ε= Bvl}ε=BvlOn putting the values we get:{ = 5 × 10^{-5} × 1.50×2}=5×10 −5 ×1.50×2{\rm { 0.15 \ mV}} 0.15 mV

Induced emf is given by: { ε= Bvl}ε=BvlOn putting the values we get:{ = 5 × 10^{-5} × 1.50×2}=5×10 −5 ×1.50×2{\rm { 0.15 \ mV}} 0.15 mV

Induced emf is given by: { ε= Bvl}ε=BvlOn putting the values we get:{ = 5 × 10^{-5} × 1.50×2}=5×10 −5 ×1.50×2{\rm { 0.15 \ mV}} 0.15 mV

Induced emf is given by: { ε= Bvl}ε=BvlOn putting the values we get:{ = 5 × 10^{-5} × 1.50×2}=5×10 −5 ×1.50×2{\rm { 0.15 \ mV}} 0.15 mV is the required answer.