Question

Answer the below 14 Questions!!


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Answer 1

$\huge\red{\mathbb {\underline {Answer}}}$

$\small\sf\green{Q1.}$ The coefficient of x² is (b) 1

$\small\sf\green{Q2.}$ The coefficient of x² is (d) -1

$\small\sf\green{Q3.}$ The coefficient of x² is (a) $\frac{\pi}{2}$

$\small\sf\green{Q4.}$ The degree of 5t-7 is (b) 1

$\small\sf\green{Q5.}$ The degree of 4-y² is (c) 2

$\small\sf\green{Q6.}$ The degree of 3 is (a) 0

$\small\sf\green{Q7.}$ The value of p(x) is (a) 3

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If x = 0

Then, p(x) = 5x - 4x² + 3

=> p(0) = 5×0 - 4(0)² + 3

=> p(0) = 0 - 0 + 3

=> p(0) = 3

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$\small\sf\green{Q8.}$ The value of p(x) is (b) -6

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If x = -1

Then, p(x) = 5x - 4x² + 3

=> p(-1) = 5×(-1) - 4(-1)² +3

=> p(-1) = -5 - 4×1 + 3

=> p(-1) = - 5 - 4 + 3

=> p(-1) = - 9 + 3

=> p(-1) = -6

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$\small\sf\green{Q9.}$ The value of p(1) is (b) 0

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If p(1),

Then, x = 1

∴ p(x) = (x-1)(x+1)

=> p(1) = (1-1)(1+1)

=> p(1) = 0 × 2

=> p(1) = 0

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$\small\sf\green{Q10.}$ The value of p(0) is (b) 2

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If p(0),

Then, t = 0

∴ p(t) = 2 + t + 2t² - t³

=> p(0) = 2 + 0 + 2(0)² - (0)³

=> p(0) = 2 + 0 + 0 - 0

=> p(0) = 2

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$\small\sf\green{Q11.}$ The value of p(2) is (a) 4

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If p(2),

Then, t = 2

∴ p(t) = 2 + t + 2t² - t³

=> p(2) = 2 + 2 + 2(2)² - (2)³

=> p(2) = 2 + 2 + 8 - 8

=> p(2) = 4

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$\small\sf\green{Q12.}$ The value of p(0) is (d) 1

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If p(0),

Then, y = 0

∴ p(y) = y² - y + 1

=> p(0) = (0)² - 0 + 1

=> p(0) = 0 - 0 + 1

=> p(0) = 1

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Answer 2

Hi Mate ✌✌✌

Answer is in the attachment

For answer refer the attachments

Hope it helps you :--)