Question

answer the below question

Answer 1

bhai mujhe bhi batao kaise bnega

Answer 2

let
$\sqrt{5 + \sqrt{5 + \sqrt{5} } } \: equals \: y$
$\sqrt{5 + y } = y$
$5 + y = {y}^{2}$
${y}^{2} - y - 5 = 0$
$\frac{1 + \sqrt{1 + 20}}{2}$
$\frac{1 + \sqrt{21}}{2}$