Question

Answer the both question 5 nd 6​

Answer 1

Answer:

$for \: problem \: (5 )\ \ \: : given \: that \: \sqrt{x} - \frac{1}{2} = 3 \\ \: \: \:implies \: \sqrt{x} = 3 + \frac{1}{2 } \\ implies \: \sqrt{x } = \frac{7}{2 } \\ implies \: x = \frac{49}{4} \\ hence \: option \: (c) \: is \: correct$

$for \: problem(6) \: \: \: {x}^{2} - 5x + 6 \\ = {x}^{2} - (3 + 2)x + 6 \\ = {x}^{2} - 3x - 2x + 6 \\ = x(x - 3) - 2(x - 3) \\ = (x - 3)( x - 2) \\ hence \: option \: (c) \: is \: correct$

Answer 2

Answer:

5) c) 49

4

6) c) (x - 2)(x - 3)

$6) {x}^{2} - 5x + 6 = 0 \\ {x}^{2} - 2x - 3x + 6 = 0 \\ x(x - 2) - 3(x - 2) = 0 \\ (x - 2)(x - 3) = 0 \\ therefore \: c)(x - 2)(x - 3) \: is \: the \: correct \: option$

$5) \sqrt{x} - \frac{1}{2} = 3 \\ \sqrt{x} = 3 + \frac{1}{2} \\ \sqrt{x} = \frac{6 + 1}{2} \\ \sqrt{x} = \frac{7}{2} \\ squaring \: on \: both \: side \: we \: get \\ x = \frac{49}{4} \\ therefore \:c) \frac{49}{4}is \: the \: correct \: option$

Hope it helps you....