Math, asked by ParveenAshraf1, 1 year ago

answer the exponent and power..
( {4}^{ - 1}  +  {6}^{ - 1} ) \times \binom{4}{3}^{ - 2}
please answer fast it's urgent...​

Answers

Answered by anjalimaurya3876
2

Step-by-step explanation:

(4-¹+6-¹)*(4/3)-²

(4-¹+6-¹)*(4/3)-²= (-4)+(-6)*(4/3)-²

(4-¹+6-¹)*(4/3)-²= (-4)+(-6)*(4/3)-²= -4-6*{(-4/3)*(-4/3)}

(4-¹+6-¹)*(4/3)-²= (-4)+(-6)*(4/3)-²= -4-6*{(-4/3)*(-4/3)}= -10*{16/9}

(4-¹+6-¹)*(4/3)-²= (-4)+(-6)*(4/3)-²= -4-6*{(-4/3)*(-4/3)}= -10*{16/9}= -160/9

(4-¹+6-¹)*(4/3)-²= (-4)+(-6)*(4/3)-²= -4-6*{(-4/3)*(-4/3)}= -10*{16/9}= -160/9= -17.77.......

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