Math, asked by khateejaahmed, 9 months ago

Answer the following:
1)Find all the factors of 4 L^2 m n (^ symbol represents to the power of L).
2) The highest common factor of 9(x^2)y, 27x(y^2) and 45(x^2)(y^2) is?
3) -15(a^2)b(c^2)/5ab.
4) x^4(it represents X to the power of 4) - x factorise.
5) xy- x- y+ 1 factorise.
6) factorise: 9(x^2)- 6x.
7) divide: 32(x^4)/16(x^2)=
8) (6y^4+ 10y^3 + 10y^2)/ 2y^2=
9) 4(a^3)(b^3)(c^3)/12abc=
10) 6(L^2)mn/1=
11) 3(L^2)mn/mn=
II. Answer the following:
1) Divide:
i) {25(x^5) - 15(x^4)} / 5(x^3).
ii) { 25(x^5) - 15(x^4)} /5.
iii){25(x^5) - 15(x^4)} /x.
iv) {25(x^5) - 15(x^4)}/ (x^2).
v) {25(x^5) - 15(x^4)} / {5(x^2) - 3x}.
2) factorise 6(x^2) + 35xy - 6(y^2).
3) factorise 2 - 32(x^2).
4) factorise i) 4(a^2) - 8a + 3.
ii) (a^2) - 1/ (b^2).​

Answers

Answered by amitnrw
2

Given : 4L²mn

To find: All factors

Solution:

answering 1st Question .

Please post Question one by one

4L²mn

= 2² × L² × m¹  × n¹

Assuming that  

2 , L , m & n are co prime numbers

Then number of Factors

(2 + 1)(2 + 1)(1 + 1)(1 + 1)

= 3 * 3 * 2 * 2

= 36

There  will be 36 Factors

Factors would be

1

2

4

L

m

n

Lm

Ln

mn

Lmn

L²m

L²n

L²mn

2L

2m

2n

2L²

2Lm

2Ln

2mn

2Lmn

2L²m

2L²n

2L²mn

4L

4m

4n

4L²

4Lm

4Ln

4mn

4Lmn

4L²m

4L²n

4L²mn

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