Answer the following:
1. The point (5,-3) lies in the quadrant
2. The point whose ordinate is 4 and which lies on y-axis is
3. The perpendicular distance of the point (4,3) from x-axis is
4. Point of intersection of the axes is called
5. The graph of x = a is a line parallel to axis.
6. Find the value of k, if x = 1, y = 1 is the solution of the equation
3x - 4y = k.
7. The cost of a table is twice the cost of a chai,,"write a linear
equation in two variables to represent this statement.
8. How many solutions are there for the linear equation 2x - 5y = 7.
9. How can we write the equation x = 7 in two variables,
10. Is (1,2) a solution of 2x + 3y = 8 ? Justify
11. Find three solutions of the equations 2x + 3y = 6
12. In which quadrant or on which axis the following points lie :
i. (2,7) ii. (-6,3) iii.(9,0) iv. (0,-4)
13. Give the geometrical representation of 2% - 6 = 0 as an equation :
6) in one variable (ii) in two variables
14. Plot the points A (4,0), B (4,4), C(0,4) in the Cartesian plane. Name the figure so
obtained by joining the points AB, BC and AC.
15. Write the following equations in the form ax + by +c= 0 and indicate the values of a, b and c
in each case : (i)-4 = V3y (ii) 2x = 4y
16. Draw the linear graph for 2x +y = 6.
17. The auto rickshaw fare in a city is charged Rs 10 for the first km and at Rs 4 per km for
subsequent distance covered. Write the linear equation to express the above statement.
Draw the graph of the linear equation.
18. If (2,0) is a solution of the linear equation 2x +3y = k, then find the value of k.
19. Check whether ( 4 , 1) is a solution of the equation 2x - y = 5
20. Write the abscissa and ordinate for the following points:
i) B(4,3) (ii) K (-6,-5)
someone please help me find answered for all these questions
Answers
Answer:
1.the point (5,-3) lies in puadrant 4
2.the point which ordinate is 4 and lies in y-axis is (0,4)
3.the perpendicular distance of the point (4,3)from x-axis is 4 unit
4.point of intersection of the axis is called origin
5.the graph of x=ais a lineparallel to y-axis
6.(x=1) (y=1)
by putting the value of x and y in the expression
3x - 4y = k
=>3×1 - 4×1=k
=>3 - 4 = -1 = k
hence k = -1
7.let the coast of the table be x
so ATQ y = 2x
=>2x-y=0
this is required linear equation in two variable
8.2x -5y = 7 for this equation their are million of solution
9.we can write this equation like
2x-x=7.-9x+10x=7 and etc
10.here x = 1 and y =2
the by putting the value of x and y in expression
=2x+3y
=2×1+3×2
=2+6
=8
so we can proofe or we can say that (1,2) is a solution for 2x+3y=8
11.2x+3y=6 (x=1)
=>2×1+3y=6
=>2+3y=6
=>3y=6-2
=>3y=4
=>y=4/3
so first solution is (1,4/3)
(x=2)
2×2+3y=6
4+3y=6
3y=6-4
3y=2
y=2/3
so second solution is (2,2/3)
(x=3)
2×3+3y=6
6+3y=6
3y=6-6
y=0/3
y=0
so third solution is (3,0)
12.i)1st
ii)2nd
iii)1st
iv)4th
Answer:
the point (5,-3) lies in puadrant 4
2.the point which ordinate is 4 and lies in y-axis is (0,4)
3.the perpendicular distance of the point (4,3)from x-axis is 4 unit
4.point of intersection of the axis is called origin
5.the graph of x=ais a lineparallel to y-axis
6.(x=1) (y=1)
by putting the value of x and y in the expression
3x - 4y = k
=>3×1 - 4×1=k
=>3 - 4 = -1 = k
hence k = -1
7.let the coast of the table be x
so ATQ y = 2x
=>2x-y=0
this is required linear equation in two variable
8.2x -5y = 7 for this equation their are million of solution
9.we can write this equation like
2x-x=7.-9x+10x=7 and etc
10.here x = 1 and y =2
the by putting the value of x and y in expression
=2x+3y
=2×1+3×2
=2+6
=8
so we can proofe or we can say that (1,2) is a solution for 2x+3y=8
11.2x+3y=6 (x=1)
=>2×1+3y=6
=>2+3y=6
=>3y=6-2
=>3y=4
=>y=4/3
so first solution is (1,4/3)
(x=2)
2×2+3y=6
4+3y=6
3y=6-4
3y=2
y=2/3
so second solution is (2,2/3)
(x=3)
2×3+3y=6
6+3y=6
3y=6-6
y=0/3
y=0
so third solution is (3,0)
12.i)1st
ii)2nd
iii)1st
Step-by-step explanation:
Ok