answer the following
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TO PROVE: AB = CD
PROOF: EA = EC ....(i) (TANGENTS FROM SAME EXTERNAL POINT)
EB = ED ....(ii) ( TANGENTS FROM SAME EXTERNAL POINT)
(i) + (ii)
EA + EB = EC + ED
=> AB = CD ( EA + EB = AB)
(EC + ED = CD)
HENCE PROVED
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Step-by-step explanation:
To Proof : AB = CD
proof : EA = EC .......(1)( tangents from same external point)
EB = ED ......(2) ( tangents from same external point)
(1) + (2)
EA+EB = EC + ED
or, AB = CD( EA +EB = AB)
(EC + ED = CD)
hence proved
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