Question

Answer the following 15sec²27-15cot²63

Answer 1

Answer:

15sec²27° – 15cot²63°

= 15sec²(90° – 63°) – 15cot²63°

= 15cosec²63° – 15cot²63°

= 15(cosec²63° – cot²63°) [cosec²A – cot²A = 1]

= 15 × 1

= 15

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Answer 2

Answer:

15sec²27° - 15cot²63°

= 15sec²27° - 15cot²( 90° - 27°)

= 15sec²27° - 15tan²27°

= 15 ( sec²27° - tan²27°)

= 15×1

= 15

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