Question

answer the following​

Answer 1

5. Electron distribution of Aluminum = 2,8,3

Electrons in last shell = 3

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6. Atomic no. = No. of protons = 3

Element = Lithium

Electronic Configuration = 2,1

Valency = 1

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7. Refer to attachment

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8.

a) 12

b) atomic mass = no. of protons + no. of neutrons

atomic mass = 12 + 12

= 24amu

c) 8

d) 0

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9. Refer to attachment

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10.

~ For (A)

Valency = 0

Valence electrons = 8

~ For (B)

Valency = 1

Valence electrons = 7