Math, asked by sarvindbhatt055, 3 months ago

answer the following​

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Answered by BlessedOne
13

Multiply :

\sf\:(i)~(6a+7b-3c) \times 4a

\sf\longrightarrow~(6a \times 4a) + (7b \times 4a) - (3c \times 4a)

\sf\longrightarrow~24a^{2} + 28ab - 12ac \sf\color{cyan}{⋆}

══════════════════‎

\sf\:(ii)~(x+4) \times (x+10)

\sf\longrightarrow~x(x+10) + 4(x+10)

\sf\longrightarrow~x^{2}+10x + 4x+40

\sf\longrightarrow~x^{2}+14x+40 \sf\color{cyan}{⋆}

══════════════════‎

\sf\:(iii)~(x+5) \times (2x+3)

\sf\longrightarrow~(x+5) \times (2x+3)

\sf\longrightarrow~x(2x+3)+5(2x+3)

\sf\longrightarrow~2x^{2}+3x+10x+15

\sf\longrightarrow~2x^{2}+13x+15 \sf\color{cyan}{⋆}

══════════════════‎

\sf~(iv)~(3x-5y) \times (2x+4y)

\sf\longrightarrow~3x(2x+4y)-5y(2x+4y)

\sf\longrightarrow~6x^{2}+12xy-10xy-20y^{2}

\sf\longrightarrow~6x^{2}+2xy-20y^{2} \sf\color{cyan}{⋆}

══════════════════‎

\sf\:(v)~(x+9y) \times (x-5y)

\sf\longrightarrow~x(x-5y)+9y(x-5y)

\sf\longrightarrow~x^{2}-5xy+9xy-45y^{2}

\sf\longrightarrow~x^{2}+4xy-45y^{2} \sf\color{cyan}{⋆}

══════════════════

‎‎

\tt\color{purple}{~~~~~~~~~~~~~~~~~~~~~~~~Thank~uh~☄}

Answered by monishaBK123
1

Step-by-step explanation:

(i) (6a +7b-3c) x 4a

→→ (6a × 4a) + (7b × 4a) – (3c × 4a

→24a2+28ab - 12ac

(ii) (x+4) x (x+10)

→ x(x+10) + 4(x+10)

→x² + 10x + 4x + 40

→x² +14x + 40

(iii) (x+5) x (2x+3)

→ (x+5) x (2x + 3)

x(2x + 3) +5(2x+3)

→ 2x² + 3x + 10x + 15

→ 2x² + 13x + 15

(iv) (3x − 5y) × (2x+4y)

→ 3x(2x+4y) — 5y(2x+4y)

→ 6x² + 12xy - 10xy - 20y²

→ 6x² + 2xy – 20y²

(v) (x +9y) × (x - 5y)

→ x(x − 5y) +9y(x - 5y)

→x²5xy + 9xy - 45y²

→x² + 4xy - 45y²

I HOPE ITS HELPFUL FOR YOU!!

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