answer the following
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as PQR is a single line so,
Angle PQS+angle SQR=180°
=> 3x+10+9x+2=180
=> 12x=180-12
=> 12x=168
=> x=168/12
=> x=14
so, angle SQP
=(3x+10)°=(3.14+10)°=(42+10)°=52°
angle SQR=(9x+2)°=(9.14+2)°=(126+2)°=128°
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1
POQ is a straight line.
3x + 10 + 9x + 2 = 180
[angles on a straight line]
12x + 12 = 180
12x = 180-12
12x = 168
x = 168/12
x = 14
• Angle SQP = 3x + 10
3*14 + 10 = 52
• Angle SQR = 9x + 2
9*14 + 2 = 128
3x + 10 + 9x + 2 = 180
[angles on a straight line]
12x + 12 = 180
12x = 180-12
12x = 168
x = 168/12
x = 14
• Angle SQP = 3x + 10
3*14 + 10 = 52
• Angle SQR = 9x + 2
9*14 + 2 = 128
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