Answer the following.
A farmer bought a buffalo for 3 45,000 and a cow for 3 20,000. He sold
the buffalo at a loss of 5% but made a profit of 10% on the cow. Find the
overall profit or loss in transactiony
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Cost price of buffalo =Rs.44000
Loss of 5%
∴Loss = (5×44000)/100 = 2200
Selling price of buffalo =Rs.44000−2200=Rs. 41800
Cost price of cow =Rs.18000
Profit of 10%
Hence, profit = (10 ×18000)/100 = 1800
So, Price=18000+1800=Rs. 19800
Cost price of both cow and buffalo
=44000+18000=Rs. 62000
Selling price of both cow and buffalo
⇒Rs.(19800+41800)=Rs.61600
∴Loss=62000−61600=Rs.400
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