Math, asked by sam575644, 2 months ago

Answer the following.
A farmer bought a buffalo for 3 45,000 and a cow for 3 20,000. He sold
the buffalo at a loss of 5% but made a profit of 10% on the cow. Find the
overall profit or loss in transactiony​

Answers

Answered by ketandayalbaghel2008
1

Answer:

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Answered by aasimfeetwala
2

Answer:

Cost price of buffalo =Rs.44000

Loss of 5%

∴Loss = (5×44000)/100 = 2200

Selling price of buffalo =Rs.44000−2200=Rs. 41800

Cost price of cow =Rs.18000

Profit of 10%

Hence, profit = (10 ×18000)/100 = 1800

So, Price=18000+1800=Rs. 19800

Cost price of both cow and buffalo

=44000+18000=Rs. 62000

Selling price of both cow and buffalo

⇒Rs.(19800+41800)=Rs.61600

∴Loss=62000−61600=Rs.400

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