Question

Answer the following
aihind the nean, median and made of the following duma
6.15.120.50.100.10.10.15.8.10.15​

Answer 1

Correct Question:

Answer the following:-

Find the mean, median and mode of the following data:

6, 15, 120, 50, 100, 10, 10, 15, 8, 10, 15​

Given:

The data:

6, 15, 120, 50, 100, 10, 10, 15, 8, 10, 15​

What To Find:

We have to find the

• Mean
• Median
• Mode

How To Find:

To find

• Mean

$\sf{Mean = \dfrac{Sum \: of \: the \: given \: observation}{Number \: of \: given \: observation}}$

• Median

i. $\sf{Median = \dfrac{N + 1}{2} - For \: Odd \: No.}$

ii. $\sf{Median =\dfrac{1}{2} \bigg[ \dfrac{N}{2} + \dfrac{N + 1}{2} \bigg] - For \: Even \: No.}$

• Mode

1. Arrange them in ascending or descending order.

2. The number that occurs most frequently is the mode.

Solution:

• Finding the mean.

Using the formula,

⇒ $\sf{Mean = \dfrac{Sum \: of \: the \: given \: observation}{Number \: of \: given \: observation}}$

Substitute the values,

⇒ $\sf{Mean = \dfrac{6+15+120+50+100+10+10+15+8+10+15}{11}}$

Add the numerator,

⇒ $\sf{Mean = \dfrac{359}{11}}$ (Can't divide)

∴ Hence, the mean is $\bf{\dfrac{359}{11}}$.

• Finding the median.

No. of observation is odd i.e 11, we will use the formula,

⇒ $\sf{Median = \dfrac{N + 1}{2}}$

Substitute the values,

⇒ $\sf{Median = \dfrac{11 + 1}{2}}$

Add the numerator,

⇒ $\sf{Median = \dfrac{12}{2}}$

Divide 12 by 2,

⇒ Median = 6

∴ Hence, the median is 6.

• Finding the mode.

Arrange the data,

⇒ 6, 8, 10, 10, 10, 15, 15, 15, 50, 100, 120

Find the number that occurs most frequently,

⇒ 10 and 15 (3 times)

∴ Hence, the mode is 10 and 15.