Math, asked by eixeralobba, 1 day ago

Answer the following and show your solutions.

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Answers

Answered by dkchakrabarty01
0

Answer:

3x^2+12x+13=(√3x)^2+2.(√3x)(2√3)+(2√3)^2-(2√3)^2+13=0

{(√3x+2√3)^2=-1=(i)^2

√3x=-i-2√3

x=(-i-2√3)/√3 and (i-2√3)/√3

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